MOLAR MASS OF CUSO4.5H2O = 249.5 gm /mol ..
given mass of CUSO4.5H2O = 0.10 g .
So , moles of CUSO4.5H2O =( 0.10 / 249.5 ) mole .
volume of water = 50 cm3 .
mass of water = 50 gm ( density of water = 1 g / ml .) .
concentration of solution in terms of molality
=
moles of solute (CUSO4.5H2O ) / mass of solvent in kg ( water).
So , Molality = (0.10 /249 .5) mole . / (50 /1000 ) kg .
So , molality = ( 0.10 * 1000 ) / ( 249.5 * 50) mol /kg . = 0.008 m .
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