Answer to Question #125151 in General Chemistry for mike

Question

A sample of limestone, CaCO3 was sealed inside a strong glass tube. The mass of the tube and limestone was found to be 156.4g. The tube was then heated over a Bunsen burner, causing the formation of some quicklime, CaO and carbon dioxide gas. The mass of the tube and its contents after the reaction would be:
A. greater than 156.4g
B. less than 156.4g
C. equal to 156.4g
D. either A, B or C depending on the mass of limestone

Answer 1

Correct option is C

Since glass tube is sealed so when reaction occurs

CaCO₃$\implies$ CaO + CO₂

No change in mass of (tube and CaCO₃) before and after reaction as mass is always conserved.