Question #125151

A sample of limestone, CaCO3 was sealed inside a strong glass tube. The mass of the tube and limestone was found to be 156.4g. The tube was then heated over a Bunsen burner, causing the formation of some quicklime, CaO and carbon dioxide gas. The mass of the tube and its contents after the reaction would be:
A. greater than 156.4g
B. less than 156.4g
C. equal to 156.4g
D. either A, B or C depending on the mass of limestone

Expert's answer

Correct option is C

Since glass tube is sealed so when reaction occurs

CaCO3    \implies CaO + CO2

No change in mass of (tube and CaCO3) before and after reaction as mass is always conserved.


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