Balance reaction
"2Mg + O2\\implies2MgO"
Moles "1.2\/24" excess 0
at t =0
At t =t 0 excess 1.2/24
Hence moles of MgO will formed according to unitary method is 1/20 moles
mass of MgO formed = 1/20 * 40
= 2 gm.
Here Mg is limiting reagent.
Mole concept will be applied according to limiting reagent.
Limiting reagent is that reagent which ends first.
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how did u got 1.2/24 excess0
I couldn't understand this solution can someone explain it to me please?
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