Answer to Question #125152 in General Chemistry for mike

Question

The reaction of sodium sulfite with hydrochloric acid may be represented by the following equation:
Na2SO3(aq) + 2HCl(aq) ⇨ 2NaCl(aq) + H2O(l) + SO2(g)
On the basis of the information in the equation, which one of the following is true?

A. When one mole of Na2SO3 is treated with acid, one mole of SO2 will always be produced.

B. Na2SO3 and HCl must always be present in the mole ratio of 1:2 for a reaction to take place

C. The ratio by mass of Na2SO3 to HCl in a reaction mixture of stoichiometric proportions is 1:2

D. 0.4mol of water will be produced when 0.8mol of HCl reacts completely with excess Na2SO3

Answer 1

Answer is "D" ..

From the reaction

2 mole of Hcl Completly react with excess of Na₂SO₃ and form 1 mole of Water is formed .

SO , When 0.8 mol of HCl reacts Completely with excess of Na₂SO₃ Then 0.4 mole Of water is formed .

Other option with Correction .

a. When one mole of Na2SO3 is completly react with excess of acid, then one mole of SO2 will be produced..

b . Na2SO3 and HCl must always reacting in the mole ratio of 1:2 for a reaction to take place.

C. Mass ratio of Na₂SO₃ and HCl for Reaction is 126 / 73 . This is completely reacting mass ratio . Of Na₂SO₃ and Hcl .........