C1=3μF,C2=6μF,C3=2μF,C4=4μF
C′=C1+C2C1C2=3+63×6×10−6=2×10−6F
C′′=C3+C4C3C4=2+42×4×10−6=34×10−6F=1.33μF
Cnet=C′+C′′=3=2+1.33=3.33μF Series combination charge is same
C=∆VQQ′=90×2=180μC Q′′=1.33×90=120μC
C1,C2 Each capacitor charge 180μC
C3,C4 each capacitor charge 120μC
C1,C2 ,C3,C4net potential
Vc1=C1Q′=3180=60VVc2=C2Q′=6180=30VVc3=C3Q′′=2120=60VVc2=C2Q′′=4120=30V
Q=CV
U=21CnetV2
U=21×3.33×10−6×902=13.4mJ
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