A parallel plate capacitor has the space between the plates filled with two slabs of dielectric, one with constant κ1 and one with constant κ2. Each slab has thickness d/2, where d is the plate separation. Show that the capacitance is C = 2ε0A /d (κ1κ2/κ1 + κ2)
For series combination the battery gives same charge and finally the same amount (Q) of charge is taken out to the negative terminal of the battery.
For series capacitance charge is the same, but the potential difference differ by "\\frac{Q}{C}"
"V=\\frac{Q}{C}"
As the question has a dielectric slab, so we take
"C = \\frac{k\u03b5_0A}{d}"
For series combination
"V= \\frac{1}{C}=\\frac{1}{C_1}+ \\frac{1}{C_2} \\\\\n\nC_1= \\frac{k\u03b5_0A_1}{d} \\\\\n\nC_2= \\frac{k\u03b5_0A_2}{d} \\\\\n\n\\frac{1}{C}=\\frac{1}{C_1}+ \\frac{1}{C_2} = \\frac{k\u03b5_0A_1}{d} + \\frac{k\u03b5_0A_2}{d} \\\\\n\nC_{cf}= \\frac{2\u03b5_0A}{d}(\\frac{k_1k_2}{k_1+k_2})"
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