Answer to Question #346090 in C++ for Umi

Question

An integer is said to be a perfect number if the sum of its divisors, including 1 (but not the number itself),

is equal to the number. For example, 6 is a perfect number, because 6 = 1 + 2 + 3. Write a function

isPerfect() that determines whether parameter number is a perfect number. Use this function in a

program that determines and prints all the perfect numbers between 1 and 1000. Print the divisors of

each perfect number to confirm that the number is indeed perfect. Challenge the power of your computer

by testing numbers much larger than 1000.

Answer 1

#include <iostream>
int main()
{
	long* divisors; int i; int j; int n = 0; long sum = 0;
	divisors = new long[10000];
	for (i = 2; i < 1000; i++)
	{
		n = 0;
		*(divisors + n) = 1;
		sum = *(divisors + n);
		n++;
		for (j = 2; j < 1000; j++)
			if (i % j == 0)
			{
				*(divisors + n) = j;
				sum = sum + j;
				n++;
			}
		if (i * 2 == sum)
		{
			std::cout << "perfect number: " << i << "\n";
			std::cout << "divisors: ";
			for (j = 0; j < n - 1; j++)
				std::cout << *(divisors + j) << " ";
			std::cout << "\n";
		}
	}
}