Answer to Question #345799 in C++ for Arun

Question

10. Consider a two-dimensional array Marks[10][5] having its base address as 2000 and the

number of

bytes per element of the array is 2. Now, compute the address of the element, Marks[8][5],

assuming that the elements are stored in row major order.

Answer 1

The adress of Marks[i][j] element of Marks[m][n] array:

Marks[i][j] adress = base adress+ size* (i*n + j-1)

Marks[8][5] adress = 2000+2* (8*5+4) = 2088

(j-1 because you want to get the beggining adress of the element)

// a typo on the 2nd line: n instead of m