Answer to Question #312092 in C++ for Izen

Question

Write a program which takes a number n as input and prints YAYY if the sum of all digits

except the rightmost digit is equal to the rightmost digit., otherwise print OOPS. (10 marks)

For example: If user enters 2237, it will print YAYY because 2+2+3 is equal to 7.

Whereas, if user enters 3425, it will print OOPS because 3+4+2 is not equal to 5. Without using loops

Answer 1

#include <iostream>
using namespace std;

int digits_sum(int n) {
    if (n == 0)
        return 0;
    return n%10 + digits_sum(n/10);
}


bool check(int n) {
    int d, sum;

    d = n % 10;
    sum = digits_sum(n/10);
        
    return sum == d;
}


int main() {
    int n;

    cin >> n;

    if (check(n)) {
        cout << "YAYY" << endl;
    }
    else {
        cout << "OOPS" << endl;
    }

    return 0;
}