Answer to Question #311911 in C++ for Minie

Question

Enter a C++ program that will help accept an input for the array size. Store the user input then display the even odd numbers.

Enter array size :: 10

Enter array elements ::

Enter arr[0] Elements :: 1

Enter arr[1] Elements :: 2

Enter arr[2] Elements :: 3

Enter arr[3] Elements :: 4

Enter arr[4] Elements :: 5

Enter arr[5] Elements :: 6

Enter arr[6] Elements :: 7

Enter arr[7] Elements :: 8

Enter arr[8] Elements :: 9

Enter arr[9] Elements :: 0

Stored Data in Array ::

1 2 3 4 5 6 7 8 9 0

Events Elements in Array are ::

2 4 6 8 0

Odd Elements in Array are ::

1 3 5 7 9

Answer 1

#include <iostream>
using namespace std;




int main() {
	int size;
	int numbers[1000];
	cout<<"Enter array size :: ";
	cin>>size;
	cout<<"Enter array elements ::\n";
	for(int i=0;i<size;i++){
		cout<<"Enter arr["<<i<<"] Elements :: ";
		cin>>numbers[i];
	}
	cout<<"Stored Data in Array ::\n";
	for(int i=0;i<size;i++){
		cout<<numbers[i]<<" ";
	}
	cout<<"\nEvents Elements in Array are ::\n";
	for(int i=0;i<size;i++){
		if(numbers[i]%2==0){
			cout<<numbers[i]<<" ";
		}
	}
	cout<<"\nOdd Elements in Array are ::\n";
	for(int i=0;i<size;i++){
		if(numbers[i]%2!=0){
			cout<<numbers[i]<<" ";
		}
	}


	cin>>size;
	return 0;
}