Answer to Question #311912 in C++ for Helpmeplss

Question

Using an array , write a C++ program that can hold ten integer input from user. Display those values on the screen , and their prompt the user an integer to search within the array , and count the number of times the item is found.

Enter 10 values in array :

1

2

3

4

5

6

7

8

8

Values in array now : 1 2 3 4 5 6 7 8 8

Enter the value to find : 8

8 was found in 2 times.

____________________________

Process excited with return value 0

Press any key continue . . .

Answer 1

#include <iostream>

using namespace std;

int main()
{
	int arr[10];
	cout << "Enter 10 values in array :";
	for (int i = 0; i < 10; i++)
	{
		cin >> arr[i];
	}
	cout << "Values in array now: ";
	for (int i = 0; i < 10; i++)
	{
		cout<< arr[i]<<" ";
	}
	int fnd;
	int count = 0;
	cout << "\nEnter the value to find :";
	cin >> fnd;
	for (int i = 0; i < 10; i++)
	{
		if (arr[i] == fnd)count++;
	}
	cout << endl;
	cout <<fnd<<" was found in "<< count<<" times";
}