Question #243087

Let G(x) = x5 + x4 + x2 + 1 be the polynomial generator(pattern), T = 101000110101110 be the message received by the destination node. Would the receiver accept the message? Why?


1
Expert's answer
2021-09-27T15:48:04-0400

Given polynomial is

G(x)=x5+x4+x2+1G(x) = x^5 +x^4+x^2+1

Message from the destination node(T)=101000110101110(T)=101000110101110

The Divisor polynomial bit =1×x5+1×x4+0×x3+1×x2+0×x+1×1=1\times x^5 +1\times x^4+0\times x^3+1\times x^2+0\times x+1\times1

=110101=110101

Bits to be appended to the message = (Divisor polynomial bits -1)=61=5=6-1= 5

Now, append 5 zero to the message bit, hence=10100011010111000000=10100011010111000000

10100011010111000000/11010110100011010111000000/110101 Remainder =0000

Hence, CRC = 0000

Hence, we will not append any digit in the original message

So, the receiver will receive 101000110101110

Because there is not any error in the code, code is correct.


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