Given polynomial is
G(x)=x5+x4+x+1
Message from the destination node(T)=11100011
The Divisor polynomial bit =1×x5+1×x4+0×x3+0×x2+1×x+1×1
=110011
Bits to be appended to the message = (Divisor polynomial bits -1)=6−1=5
Now, append 5 zero to the message bit, hence=1110001100000
1110001100000/110011 Remainder =1000
Hence, CRC = 1110
Hence, we have to append 1110 to the frame.
So, the receiver will receive 111000111110
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