Sodium chloride has a face-centered cubic (FCC) crustal lattice. First, find the packing efficiency.
The volume of the cubic unit cell:
"V=a^3=(\\sqrt8r)^3=8\\sqrt8r^3." The volume of space that the atoms occupy:
"v=4\u00b7\\frac43\\pi r^3=\\frac{16}{3}\\pi r^3." The packing efficiency:
"\\epsilon=\\frac vV=\\frac{16\\pi r^3\/3}{8\\sqrt8 r^3}=0.74." Find the density:
"\\rho=\\frac{n\\Mu}{VN_A}=\\frac{n(\\Mu_\\text{Na}+\\Mu_\\text{Cl})}{(8\\sqrt8r^3)(N_A)}=\\\\\\space\\\\\n=\\frac{4(23\u00b710^{-3}+35.5\u00b710^{-3})}{(0.563\u00b710^{-9})^3\u00b7(6.023\u00b710^{23})}=2177\\text{ kg\/m}^3."
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