Answer to Question #236482 in Physics for shiyria

Question #236482

A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long,

what is the acceleration of the jet?


1
Expert's answer
2021-09-13T11:01:04-0400

According to the kinematic equation, the distance travelled by the fighter jet is given as follows (see https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/a/what-are-the-kinematic-formulas):


Δx=vf2vi22a\Delta x = \dfrac{v_f^2 - v_i^2}{2a}

where vf=75m/s,vi=0m/sv_f = 75m/s, v_i = 0m/s are final and initial speeds of the jet respectively, aa is its acceleration. Assuming Δx=100m\Delta x = 100m, obtain:


a=vf2vi22Δxa=752022100=28.125m/s2a = \dfrac{v_f^2 - v_i^2}{2\Delta x} \\ a = \dfrac{75^2 -0^2}{2\cdot 100} = 28.125 m/s^2

Answer. 28.125m/s228.125 m/s^2.


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