Answer to Question #236482 in Physics for shiyria

Question

A fighter jet is catapulted off an aircraft carrier from rest to 75 m/s. If the aircraft carrier deck is 100 m long,

what is the acceleration of the jet?

Answer 1

According to the kinematic equation, the distance travelled by the fighter jet is given as follows (see https://www.khanacademy.org/science/physics/one-dimensional-motion/kinematic-formulas/a/what-are-the-kinematic-formulas):

$$\Delta x = \dfrac{v_f^2 - v_i^2}{2a}$$

where $v_f = 75m/s, v_i = 0m/s$ are final and initial speeds of the jet respectively, $a$ is its acceleration. Assuming $\Delta x = 100m$, obtain:

$$a = \dfrac{v_f^2 - v_i^2}{2\Delta x} \\ a = \dfrac{75^2 -0^2}{2\cdot 100} = 28.125 m/s^2$$

Answer. $28.125 m/s^2$.