Question #236512
a brick of weight 3000gf and size 25cm x 10cm x 6cm is placed in three different positions on the ground. Find the pressure exerted by the brick in each position on the ground.
1
Expert's answer
2021-09-13T12:16:34-0400

(a)

P=FA=mgab,P=\dfrac{F}{A}=\dfrac{mg}{a\cdot b},P=3000 gf9.8103 N1 gf0.25 m0.1 m=1176 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.1\ m}=1176\ Pa.

(b)

P=FA=mgac,P=\dfrac{F}{A}=\dfrac{mg}{a\cdot c},P=3000 gf9.8103 N1 gf0.25 m0.06 m=1960 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.06\ m}=1960\ Pa.

(c)

P=FA=mgbc,P=\dfrac{F}{A}=\dfrac{mg}{b\cdot c},P=3000 gf9.8103 N1 gf0.1 m0.06 m=4900 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.1\ m\cdot 0.06\ m}=4900\ Pa.

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