Answer to Question #236512 in Physics for Lily

Question

a brick of weight 3000gf and size 25cm x 10cm x 6cm is placed in three different positions on the ground. Find the pressure exerted by the brick in each position on the ground.

Answer 1

(a)

$$P=\dfrac{F}{A}=\dfrac{mg}{a\cdot b},$$ $$P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.1\ m}=1176\ Pa.$$

(b)

$$P=\dfrac{F}{A}=\dfrac{mg}{a\cdot c},$$ $$P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.06\ m}=1960\ Pa.$$

(c)

$$P=\dfrac{F}{A}=\dfrac{mg}{b\cdot c},$$ $$P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.1\ m\cdot 0.06\ m}=4900\ Pa.$$