2021-09-13T00:15:17-04:00
a brick of weight 3000gf and size 25cm x 10cm x 6cm is placed in three different positions on the ground. Find the pressure exerted by the brick in each position on the ground.
1
2021-09-13T12:16:34-0400
(a)
P = F A = m g a ⋅ b , P=\dfrac{F}{A}=\dfrac{mg}{a\cdot b}, P = A F = a ⋅ b m g , P = 3000 g f ⋅ 9.8 ⋅ 1 0 − 3 N 1 g f 0.25 m ⋅ 0.1 m = 1176 P a . P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.1\ m}=1176\ Pa. P = 0.25 m ⋅ 0.1 m 3000 g f ⋅ 1 g f 9.8 ⋅ 1 0 − 3 N = 1176 P a . (b)
P = F A = m g a ⋅ c , P=\dfrac{F}{A}=\dfrac{mg}{a\cdot c}, P = A F = a ⋅ c m g , P = 3000 g f ⋅ 9.8 ⋅ 1 0 − 3 N 1 g f 0.25 m ⋅ 0.06 m = 1960 P a . P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.06\ m}=1960\ Pa. P = 0.25 m ⋅ 0.06 m 3000 g f ⋅ 1 g f 9.8 ⋅ 1 0 − 3 N = 1960 P a . (c)
P = F A = m g b ⋅ c , P=\dfrac{F}{A}=\dfrac{mg}{b\cdot c}, P = A F = b ⋅ c m g , P = 3000 g f ⋅ 9.8 ⋅ 1 0 − 3 N 1 g f 0.1 m ⋅ 0.06 m = 4900 P a . P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.1\ m\cdot 0.06\ m}=4900\ Pa. P = 0.1 m ⋅ 0.06 m 3000 g f ⋅ 1 g f 9.8 ⋅ 1 0 − 3 N = 4900 P a .
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