Question #236512

a brick of weight 3000gf and size 25cm x 10cm x 6cm is placed in three different positions on the ground. Find the pressure exerted by the brick in each position on the ground.

Expert's answer

(a)

P=FA=mga⋅b,P=\dfrac{F}{A}=\dfrac{mg}{a\cdot b},P=3000 gf⋅9.8⋅10−3 N1 gf0.25 m⋅0.1 m=1176 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.1\ m}=1176\ Pa.

(b)

P=FA=mga⋅c,P=\dfrac{F}{A}=\dfrac{mg}{a\cdot c},P=3000 gf⋅9.8⋅10−3 N1 gf0.25 m⋅0.06 m=1960 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.25\ m\cdot 0.06\ m}=1960\ Pa.

(c)

P=FA=mgb⋅c,P=\dfrac{F}{A}=\dfrac{mg}{b\cdot c},P=3000 gf⋅9.8⋅10−3 N1 gf0.1 m⋅0.06 m=4900 Pa.P=\dfrac{3000\ gf\cdot\dfrac{9.8\cdot10^{-3}\ N}{1\ gf}}{0.1\ m\cdot 0.06\ m}=4900\ Pa.
LATEST TUTORIALS
APPROVED BY CLIENTS