Question

A diverging lens has a focal length of 10.0 cm. An object 1.5 m tall is placed 50.0 cm in front of the lens. Locate the image. Determine both the magnification and the height of the image. Describe the image.

Answer 1

$1/a+1/b=-1/F\to 1/0.5+1/b=-1/0.1\to b=-0.083\ (m)$

$\beta=-(-0.083/0.5)=0.167$

$\beta=h/H\to h=H\cdot\beta=1.5\cdot0.167=0.25 \ (m)$

The image is reduced, virtual and direct.