Question

An elevator weighing 4000 Ib attains an upward velocity of 4 m/sec in 3 sec with uniform acceleration. Find the apparent weight of a 40 kg man standing inside the elevator during its ascent.

Answer 1

$N-mg=ma\to N=m(g+a)$

$v=at\to a=v/t=4/3\approx1.33\ (m/s^2)$

$N=m(g+a)=40\cdot(9.81+1.33)=445.73\ (N)$ . Answer