Answer to Question #209920 in Physics for Rainie

Question #209920

The escape velocity from the surface of the earth of radius R is v. What is the escape velocity from a height of 2R?

Expert's answer

"mv_0^2\/2-GMm\/R=0\\to v_0=\\sqrt{2GM\/R}"

"mv^2\/2-GMm\/(2R)=0\\to v=\\sqrt{GM\/R}=v_0\/\\sqrt{2}" . Answer

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