An elevator weighing 4000 Ib attains an upward velocity of 4 m/sec in 3 sec withuniform acceleration. Find the apparent weight of a 40 kg man standing inside the elevator during its ascent
"N-mg=ma\\to N=m(g+a)"
"v=at\\to a=v\/t=4\/3\\approx1.33\\ (m\/s^2)"
"N=m(g+a)=40\\cdot(9.81+1.33)=445.73\\ (N)" . Answer
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