Answer to Question #191515 in Physics for Kageyama

Question

A defibrillator passes 10.27 A of current through the torso of a person for 11.4 ms. How many electrons (in x10¹⁵) pass through the wires connected to the patient?

0 Decimals Answer

Answer 1

The charge can be expressed in terms of current and time:

$$Q=It.$$

This charge is made of N electrons each of charge e:

$$N=\frac Qe=\frac{It}{e}=7.3·10^{17}.$$