Answer to Question #191451 in Physics for joyce

Question

How large a force F is needed in the figure to pull out the 6.0 kg block with an

acceleration of 1.50 m/s

ଶ

if the coefficient of friction at its surface (this coefficient of

friction pertains to the friction between the 6kg block and the floor, and the between

6kg block and 2kg block. Therefore there will be two friction forces.)

Answer 1

$$F-\mu (M+m)g-\mu mg=Ma\\ F-0.42 (6+2)(9.8)-0.42 (2)(9.8)=(6)(1.5)\\F=50.2\ N$$