Question #178083

Find the electric field at point P due to charges q1 and q1 shown below.



q1: 40.0 C

q2: -40.0 C

Distance between q1 and q2 is 40.0 cm

Then a line right through the middle of q1 and q2 going up to point P.

That line is 25 cm long and make an angle of 90 degrees.





I would like to add a picture for clarification but there isn't any option to. How may I do it?

Expert's answer

E=kq1r2kq1r2E=910940(40)(0.2)2=1.81013VmE=k\frac{q_1}{r^2}-k\frac{q_1}{r^2}\\ E=9\cdot10^9\frac{40-(-40)}{(0.2)^2}=1.8\cdot10^{13}\frac{V}{m}


LATEST TUTORIALS
APPROVED BY CLIENTS