Answer to Question #178065 in Physics for Fwangshak Lekshak

Question

find the resultant of two forces of 4N and 5N is. 1. they are inclined perpendicular to each other. 2. they are inclined at 35⁰ to each other. 3. they are inclined at 145⁰ to each other

Answer 1

1)

$$R=\sqrt{4^2+5^2+2(4)(5)\cos{90}}=6.4\ N$$

2)

$$R=\sqrt{4^2+5^2+2(4)(5)\cos{35}}=8.6\ N$$

3)

$$R=\sqrt{4^2+5^2+2(4)(5)\cos{145}}=2.9\ N$$