Answer to Question #178057 in Physics for Abdul Abduli

Question

In the process of fission, where an atomic nucleus bursts apart into two pieces, the pieces tend to fly apart at about 3% of the speed of light. For a particular nucleus with mass 4.98*10^(-27) kg, one piece moves to the left with a speed of 9*10^6 m/s, while the other piece with a mass of 3.32*10^(-27) kg moves to the right. What is the velocity of the second piece? (Define right to be the positive direction.) *

4.5*10^6 m/s

-4.5*10^6 m/s

1.35*10^7 m/s

-1.35*10^7 m/s

8.6*10^7 m/s

-8.6*10^7 m/s

Answer 1

$$m_1v_1=m_2v_2\\(4.98\cdot10^{-27})(9\cdot10^{6})=(3.32\cdot10^{-27})v_2\\v_2=1.35\cdot10^{7}\frac{m}{s}$$