Question

Calculate the magnitude of magnetic intensity H vector and magnetic field B vector at the centre of a 2500 turn solenoid which is 0.50 m long and carries a current of 1.0A

Answer 1

Let's first find the magnetic field at the centre of a solenoid:

$$B=\dfrac{\mu_0NI}{L},$$ $$B=\dfrac{4\pi\cdot10^{-7}\ \dfrac{Tm}{A}\cdot2500\cdot 1.0\ A}{0.5\ m}=6.28\cdot10^{-3}\ T.$$

Then, we can calculate the magnitude of magnetic intensity:

$$B=\mu_0H,$$ $$H=\dfrac{B}{\mu_0}=\dfrac{6.28\cdot10^{-3}\ T}{4\pi\cdot10^{-7}\ \dfrac{Tm}{A}}=4997\ \dfrac{A}{m}.$$

Answer:

$B=6.28\cdot10^{-3}\ T, H=4997\ \dfrac{A}{m}.$