if a car passes four station with a constant acceleration the station are named a,b,c,and d initially at rest if Vi=2Vc, Vd=3Vc and the distance traveled from B to c is 200m. find the total distance traveled?
The condition of the problem is incorrect, so it will not be solved.
Assume that "v_0=0" , "v_c=2v_b" , "v_d=3v_b"
"a=const" and "BC=200 (m)" .
"s_2=\\frac{(2v_b)^2-v_b^2}{2a}\\to a=\\frac{3v_b^2}{2s_2}"
"s_1=\\frac{v_b^2-0}{2a}=\\frac{v_b^2}{2\\cdot 3v_b^2}\\cdot2s_2=\\frac{200}{3}\\approx67(m)"
"s_3=\\frac{(3v_b)^2-(2v_b)^2}{2a}=\\frac{5v_b^2}{2\\cdot 3v_b^2}\\cdot2s_2=\\frac{5\\cdot2\\cdot200}{2\\cdot3}\\approx333(m)"
"s=s_1+s_2+s_3=67+200+333=600(m)" . Answer
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