Question

if a car passes four station with a constant acceleration the station are named a,b,c,and d initially at rest if Vi=2Vc, Vd=3Vc and the distance traveled from B to c is 200m. find the total distance traveled?  

Answer 1

The condition of the problem is incorrect, so it will not be solved.

Assume that $v_0=0$ , $v_c=2v_b$ , $v_d=3v_b$

$a=const$ and $BC=200 (m)$ .

$s_2=\frac{(2v_b)^2-v_b^2}{2a}\to a=\frac{3v_b^2}{2s_2}$

$s_1=\frac{v_b^2-0}{2a}=\frac{v_b^2}{2\cdot 3v_b^2}\cdot2s_2=\frac{200}{3}\approx67(m)$

$s_3=\frac{(3v_b)^2-(2v_b)^2}{2a}=\frac{5v_b^2}{2\cdot 3v_b^2}\cdot2s_2=\frac{5\cdot2\cdot200}{2\cdot3}\approx333(m)$

$s=s_1+s_2+s_3=67+200+333=600(m)$ . Answer