Question

Find the value of the acceleration due to gravity of a body of mass 0.6kg and at a distance of 6×10^-6 from the moon [G=6.7×10^-11Nm²kg^-2]

Answer 1

$$g_M=\dfrac{GM_M}{(R_{M}+h)^2},$$ $$g_M=\dfrac{6.7\cdot10^{-11}\ \dfrac{Nm^2}{kg^2}\cdot 7.36\cdot10^{22}\ kg}{(1.737\cdot10^6\ m+6\cdot10^6\ m)^2}=0.082\ \dfrac{m}{s^2}.$$

Answer:

$g_M=0.082\ \dfrac{m}{s^2}$