Answer to Question #120121 in Physics for Peuyehafo

Question #120121
Find the Reynolds number if a fluid of viscosity 0.4 Ns/m2 and relative density of 900 kg/m3
through a 20 mm pipe with a velocity of 2.5 m/s. Is the flow Laminar or Turbulent?
Note: If Reynolds < 2000 the flow is laminar
If Reynolds > 4000 the flow is turbulent
If 2000 < Re < 4000 it is transitional flow
Re =
1
Expert's answer
2020-06-04T09:58:08-0400

The Reynolds number is given by the following expression:


Re=ρuDμ\mathrm{Re} = \frac{\rho u D}{\mu}

where ρ=900kg/m3\rho = 900 kg/m^3 is the relative density of the fluid, u=2.5m/su = 2.5 m/s is the velocity of the fluid, D=0.02mD = 0.02 m is the diameter of the pipe and μ=0.4Ns/m2\mu = 0.4 N\cdot s/m^2.

Substituting values, obtain:


Re=9002.50.020.4=112.5\mathrm{Re} = \frac{900\cdot 2.5 \cdot 0. 02}{0.4} = 112.5

As far as 112.5<2000, the flow is laminar.


Answer. Re = 112.5, laminar flow.


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