Answer to Question #120094 in Physics for Asif Sultan

Question

Two charges q1 and q2 separated by a dielectric constant 4 repel each other with a force of 10N, another charge q3 is placed between q1 and q2 such that the distance of q3 from q1 is 1/4 times the distance of q3 from q2. Now, the force of repulsion between q1 and q2 is?

Answer 1

The force of repulsion between q1 and q2 remains the same, namely, 10N. This is true due to thesuperposition principle of the electrical fields. The intaraction between two point charges does not depend on any other charges located around.