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Lens Equation

Solve the following problems.

1.An object 8 cm tall is placed 30 cm from a converging lens. A real image is

formed 15 cm from the lens. (5 pts.)

          a. What is the focal length of the lens?

          b. What is the size of the image?

          c. Describe the image using the ray diagram.

2.A diverging lens has a focal length of 2.5 cm. If it is placed 4 cm from an object, at

what distance from the lens will the image be located? Describe the image. (3pts.)



the visible light of wavelength 350 NM to 800 NM is incident normally on a thin film with refractive index 4 it is observed that three wavelength 720 NM, 480 NM and 360 NM are compulsory missing from reflected spectra find the minimum thickness of a film.
You have an infrared laser that produces light of an unknown wavelength.
A. You shine this laser through a mask containing a single slit of width a. On a screen that is a
distance L away, you find a very broad bright spot at the center of the screen that has a width of
L. Determine the wavelength of the laser in terms of the given quantities.
B. You shine the same laser through a different mask containing a single slit that
calculate the coherence time and coherence length of white light of wave length range of 3500 angstrom to 6500 angstrom
what is a virtual image?
Suppose the first-order maximum for 475 nm blue light being transmitted through a diffraction grating is at an angle of 22°.

Randomized Variables
λ = 475 nm
θ = 22°


How many lines per centimeter are there on this diffraction grating?
.A small convex mirror is placed 60 cm from the pole and on the axis of a large concave mirror of radius of curvature 200 cm.The position of the convex mirror is such that a real image of distant object is formed on the plane of a hole drilled through the concave mirror at its pole. Calculate ‘R’ of convex mirror and height of the real image if distant object forms 0.5 degree angle at the pole of the concave mirror.
You are interested in generating 532nm light, but you only have access to a high power laser whose emission wavelength is 1064nm. You also have access to a non-centrosymmetric birefringent crystal with the following refractive indices at these two frequencies: no(ω) = 1.4938, ne(ω) = 1.4599, no(2ω) = 1.5124, ne(2ω) = 1.4705. Additionally, it is known that for this crystal, the only non zero components of the nonlinear coefficient matrix (so called d−matrix) are d14, d25, d36. You are not allowed to cut or heat up the crystal – you can only rotate it. Find out the correct alignment of this crystal to maximize the second harmonic generation.
(a) Find the orientation of the crystal with respect to the electric field of the incident fundamental wave for maximizing the second harmonic generation efficiency.
(b) Draw a picture showing all the polarization directions, propagation directions of the fundamental and second harmonic waves and the crystal orientation for this set up.
Suppose the first-order maximum for 475 nm blue light being transmitted through a diffraction grating is at an angle of 22°.

Randomized Variables
λ = 475 nm
θ = 22°


How many lines per centimeter are there on this diffraction grating?
Suppose the first-order maximum for 475 nm blue light being transmitted through a diffraction grating is at an angle of 22°.

Randomized Variables
λ = 475 nm
θ = 22°


How many lines per centimeter are there on this diffraction grating?
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