As per the question,
Slit width = a
Distance between the screen and slit = L
We know that width of the central maxima = "\\frac{2\\lambda D}{d}"
Now substituting the values as per the given question,
"L=\\frac{2\\lambda L}{a}"
Hence, "\\lambda = \\frac{a}{2}"
and we know that "x=\\frac{2\\lambda D}{d}"
Hence, "x\\propto \\frac{1}{d}"
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