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what is Fabry-Perot Interferometer?
Light is incident normal to a liquid layer of refractive index 1.33 that lies on top of a flat flint glass. The light will take 3.73x10^-11 s of more time to traverse through these two layers than the same distance in air. Find the refractive index of flint glass if the widths of liquid and glass layers are 1.5cm and 1.0cm.
Consider a makeup mirror that produces a magnification of 1.3 when a person’s face is 13 cm away.
What is the focal length of the makeup mirror in meters?

A concave spherical mirror is produced 18.00mm inverted image of object of object 9.00mm tall and distance between object and the mirror is 15.0cm. find radius of curvature of the mirror. 


A convex lens of focal length of 2cm is used to view an object of height 2mm. What is the angular magnification, position of the object and the height of the image if the final image is formed at the near point?
Calculate the resolving power of a grating at second order when sodium light 589 NM gets diffracted resolving 0.6 NM find lines

If the light ray moves from inside the glass toward the glass-air interface at an angle of 35.0° to the normal, determine the angle of refraction. The ray bends ________° away from the normal, as expected.


submarine is 20m below the surface of the sea.The pressure due to the water at the depth is P.On anotherday, the submarine is 26m below the surface of the fresh water.The density of sea is 1.3times the density of fresh water.What is the pressure due to the fresh water at a depth of 26m?
A 2.5 cm-tall object stands in front of a converging lens. It is desired that a virtual image 2.2 times larger than the object be formed by the lens. How far from the lens (in cm) must the object be placed to accomplish this task, if the final image is located 12 cm from the lens?
Why can we see our real and inverted image inside a concave mirror when the image is formed in front of it and not behind?

Sir if you say that if our eyes try to image the real image formed by the mirror in the mirror it self then-

Imagine a situation where we have a concave mirror is of large size and we ourself is object and we are directly seeing in the concave mirror and moving backwards so when I stand between focus and poleI see my virtual image slowly when I move backward between focus and centre of curvature then my image must be forming behind me then how my eyes are able to see my real image in the mirror….

Sir to image the real image my eyes must see the image first but in this case how without seeing the image my eyes can see the real image in the mirror it self…..

Sir please answer me in detail