In general p=ρ⋅g⋅hp=\rho\cdot g\cdot hp=ρ⋅g⋅h
The pressure due to the fresh water p0=ρ⋅g⋅h0=ρ⋅g⋅26→ρ⋅g=p026p_0=\rho \cdot g\cdot h_0=\rho \cdot g \cdot 26 \to \rho \cdot g=\frac{p_0}{26}p0=ρ⋅g⋅h0=ρ⋅g⋅26→ρ⋅g=26p0
The pressure due to the sea water p=1.3ρ⋅g⋅h=1.3ρ⋅g⋅20→ρ⋅g=p1.3⋅26p=1.3\rho \cdot g\cdot h=1.3\rho \cdot g \cdot 20 \to \rho \cdot g=\frac{p}{1.3\cdot26}p=1.3ρ⋅g⋅h=1.3ρ⋅g⋅20→ρ⋅g=1.3⋅26p
We have p026=p1.3⋅26→p0=p\frac{p_0}{26}=\frac{p}{1.3\cdot26} \to p_0=p26p0=1.3⋅26p→p0=p
So, the pressure will be the same.
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