Angular magnification is
"M=1+\\frac{25\\text{ cm}}{f}"Thus,"M=13.5" .
As, given "f=2cm,v=-25cm" and since
"\\frac{1}{f}=\\frac{1}{v}-\\frac{1}{u}\\\\\\implies 1\/2=-1\/25-1\/u\\implies u=-50\/27\\approx1.85 cm"Since, image formed at near point, linear magnification is
"m=M=h_i\/h_o\\implies h_i=Mh_o=2.7cm"
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