(i)
d=Np1=30010−3Np=300×103λ1=400×10−9mλ2=600×10−9mdsinθ1=nλ130010−3×sinθ1=3×400×10−9sinθ1=12×3×10−2θ1=sin−1(0.36)θ1=21.1°30010−3sinθ2=3×λ230010−3sinθ2=3×600×10−9θ2=sin−1(0.54)θ2=32.68°Δθ=θ2−θ1Δθ=32.68−21.1=11.58°
(ii)
dsinθ1∗=nmλ1n=1.33m=3θ1∗=sin−1(1.333×400×10−9×300×103)θ1∗=sin−1(0.2706)=15.699°dsinθ2∗=nmλ2λ2=600×10−9mθ2∗=sin−1(1.333×600×10−9×300×103)θ2∗=sin−1(0.406)=23.953°Δθ∗=θ2∗−θ1∗Δθ∗=23.953−15.699=8.254°
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