The diver sees the sun at an angle of 50 ° above the horizon. Find the angle at which a fisherman in a boat on the surface of the water sees the Sun, again relative to the horizon. The refractive index of water is 1.33.
θγ = 90 – 50 = 40º
"n_{air}sin\u03b8_i = n_{water}sin\u03b8_\u03b3 \\\\\n\n1 \\times sin\u03b8_i = 1.33 sin40\u00ba \\\\\n\n\u03b8_i = sin^{-1}(1.33 \\times sin40\u00ba) \\\\\n\n= 58.75\u00ba"
φ = 90 – 58.75 = 31.25º
31.25º is the angle at which a fisherman in a boat on the surface of the water sees the Sun, again relative to the horizon.
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