Given,
Object distance (u) = 0.25m
Focal length of the concave mirror (f)=0.6m
Length of the object (ho)=0.38m
Let position of image be at v distance from the concave mirror.
Now, applying the mirror formula,
v1+u1=f1
Now, substituting the values,
v1=f1−u1
for the concave mirror, focal length always will be negative. so
v1=0.61−0.251
⇒v1=0.1500.25−0.6
⇒v1=0.15−0.35
v=7−3cm
Hence the height of the image hi=u−ho×v=73×0.38cm
hi=71.14cm=0.16cm
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