In the arrangement, an object of mass m = 5.00kg hangs from a cord around a light pulley. the length of the cord between the point p and the pulley is L = 2.00 meters.
(a) when the vibrator is set to a frequency of 150Hz, a standing wave with 6 Loops is formed. What must be the linear mass density of the cord?
(b) How many Loops if any will result if m is changed to 45.0 kilograms?
L = 2 m; n = 6; T = 49 N; f = 150 hz; m = 5 kg
a)
v = f
L = 0.5n
= 2L / n
v = (T / M)1/2
M =
b) m = 45 kg
45 / 5 = 9
n =
n =
Answer: a) M = 0.0049kg; b) n = 2.
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