As per the given question,
We know that I=Iocos2θ
When any ray of light is passing through any polarizer then, it's intensity becomes, 1/2 of the initial intensity of light,
⇒Io/2=Iocos2θ
⇒cos2θ=21
⇒cosθ=21=cos45∘
θ=45∘
b) Now, I2=I1cos2θ
I2=2Iocos2(10+8R)
Here the value of R is not given,
c) As per the question I2=(R+1)%ofIo/2
⇒(R+1)2×100Io=2Iocos2(10+8R)
⇒100(R+1)=cos2(10+8R)
value of R must be given.
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