Question

An object is placed 0.42 m away from a concave lens and has a height of 0.09 m . The image produce is -0.05 m tall. Where is the image located?

Answer 1

using formula of magnification

$m=\dfrac vu=\dfrac IO\\$

$\dfrac{v}{-0.42}=\dfrac{-0.05}{0.09}\\v=0.23 m$

$\dfrac{}{}$