Question #110877
A concave mirror has a focal length of 0.25 m. If an object produces a virtual image 0.04 m from the mirror, where is it located?
1
Expert's answer
2020-04-21T10:53:17-0400

As per the given question,

Focal length of the concave mirror(f)=0.25m

position of virtual image form the mirror (v)=0.04m

let the position of the object from the concave mirror (u)=?

Now, applying the mirror formula,

1u+1v=1f\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

1u=10.2510.04\dfrac{1}{u}=\dfrac{1}{-0.25}-\dfrac{1}{0.04}

1u=425=29\Rightarrow \dfrac{1}{u}=-4-25=-29

u=129mu=\dfrac{1}{29}m

u=3.44cmu=3.44cm


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