Answer to Question #110877 in Optics for Nya

Question

A concave mirror has a focal length of 0.25 m. If an object produces a virtual image 0.04 m from the mirror, where is it located?

Answer 1

As per the given question,

Focal length of the concave mirror(f)=0.25m

position of virtual image form the mirror (v)=0.04m

let the position of the object from the concave mirror (u)=?

Now, applying the mirror formula,

$\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}$

$\dfrac{1}{u}=\dfrac{1}{-0.25}-\dfrac{1}{0.04}$

$\Rightarrow \dfrac{1}{u}=-4-25=-29$

$u=\dfrac{1}{29}m$

$u=3.44cm$