a)
As per the given question,
wavelength of the yellow light (λ)=589.3nm=589.3×10−9m
λ1=435nm
Angle=105.4∘
dsinθ=nλ
⇒d=sinθnλ=sin105.4∘7×589.3×10−9 m
m=λ1dsinθ=sin105.4∘×435×10−97×589.3×10−9sin105.4∘
=4357×589.3=9
b) n=5
angle (θ)=94.1∘
d=1.67microns=1.67×10−6m
dsinθ=nλ
λ=ndsinθ=51.67×10−6sin(94.1)
λ=0.33×10−6m
Comments