Question

The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?

Answer 1

Given:

initial velocity =u

angle of projectile=45^o

maximum hight achived=3.7m

solution:

according o projectile motion,

maximum hight achived by projectile is:

$h={u^2cos^2\theta \over 2g}$

$3.7={u^2 cos^245^o \over 20}$

$u^2=148$

u=12.6 m/s .............answer