Steady Flow Energy Equation
h1+2v12+gz1+Q=h2+2v22+gz2+Wh1+2v12=h2+2v22+Wh1=p1V1+u1h2=p2V2+u2p1V1+u1+2v12=h2+2v22+Wp1=400psia=400×122lb/ft2p2=40psia=40×122lb/ft2v1=300fpsv2=1100fpsV1=1.2ft3/lbV2=9ft3/lbu1−u2=30BTU/lb=23345.04ftlbp1V1+(u1−u2)+2v12=p2V2+2v22+W400×144×1.2+23345.04+23002=40×144×9+211002+W69120+23345.04+45000=51840+605000+WW=−519374.96poundalft/lbW=−667.43BTU/lb
Hence the work is negative so that the work is done on the system.
Workrate=W×massflowrate=667.43×11=7341.74BTU/min=42.47341.74=173.15HP
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