Answer to Question #267525 in Molecular Physics | Thermodynamics for MaTMaT

Question #267525

Air flows steadily through an engine at a constant temperature of 400k. Find the work per kilogram if the exit pressure is one-third the inlet pressure and the inlet pressure is 207 KPa. Assume that the kinetic energy and potential energy variation are negligible.


1
Expert's answer
2021-11-17T18:30:39-0500

Solution;

Given;

T1=T2=400KT_1=T_2=400K

P1=27kPaP_1=27kPa

P2=P13=2073=69kPaP_2=\frac{P_1}{3}=\frac{207}{3}=69kPa

Work done per kilogram;

m=1kgm=1kg

Temperature is constant,hence the process is isothermal;

W=mRTln(P1P2)W=mRTln(\frac{P_1}{P_2})

R=287J/kg.KR=287J/kg.K

W=1×287×400×ln20769W=1×287×400×ln\frac{207}{69}

W=126120.6907JW=126120.6907J

W=126.12kJW=126.12kJ


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