Air flows steadily through an engine at a constant temperature of 400k. Find the work per kilogram if the exit pressure is one-third the inlet pressure and the inlet pressure is 207 KPa. Assume that the kinetic energy and potential energy variation are negligible.
Solution;
Given;
"T_1=T_2=400K"
"P_1=27kPa"
"P_2=\\frac{P_1}{3}=\\frac{207}{3}=69kPa"
Work done per kilogram;
"m=1kg"
Temperature is constant,hence the process is isothermal;
"W=mRTln(\\frac{P_1}{P_2})"
"R=287J\/kg.K"
"W=1\u00d7287\u00d7400\u00d7ln\\frac{207}{69}"
"W=126120.6907J"
"W=126.12kJ"
Comments
Leave a comment