A volume of 400 cc of air is measured at a pressure of 740 mm Hg abs and a temperature of 18°C. what will be the volume at 760 mm Hg abs and 0°C?
V1=400 ccp1=740 mmHgT1=18+273=291 Kp2=760 mmHgT2=0+273=273 Kp1V1T1=p2V2T2V2=p1V1T2T1p2V2=740×400×273291×760=365.4 ccV_1 = 400 \;cc \\ p_1 = 740 \;mmHg \\ T_1 = 18 +273 = 291 \;K \\ p_2 = 760 \;mmHg \\ T_2 = 0 +273 = 273 \;K \\ \frac{p_1V_1}{T_1} = \frac{p_2V_2}{T_2} \\ V_2 = \frac{p_1V_1T_2}{T_1p_2} \\ V_2 = \frac{740 \times 400 \times 273}{291 \times 760} = 365.4 \;ccV1=400ccp1=740mmHgT1=18+273=291Kp2=760mmHgT2=0+273=273KT1p1V1=T2p2V2V2=T1p2p1V1T2V2=291×760740×400×273=365.4cc
Answer: 365.4 cc
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments