An ideal gas at 45 psig and 80°F is heated in a closed container to 130°F. What is the final pressure?
In a closed container volume is constant. At constant volume by Charle’s law
p2p1=T2T1T1=80 °F=299.8 KT2=130 °F=327.5 Kp2=T2p1T1p2=327.5×45299.8=49.15 psi\frac{p_2}{p_1} = \frac{T_2}{T_1} \\ T_1 = 80 \;°F = 299.8 \;K \\ T_2 = 130 \;°F = 327.5 \;K \\ p_2 = \frac{T_2p_1}{T_1} \\ p_2= \frac{327.5 \times 45}{299.8} = 49.15 \;psip1p2=T1T2T1=80°F=299.8KT2=130°F=327.5Kp2=T1T2p1p2=299.8327.5×45=49.15psi
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