Determine the net heat transfer through the black body disc with radius1cm and mass 6g, at 00C when transferred to a surrounding temperature of 100C.
r=1 cm=0.01 mTenv=10 C=283 KT=0 C=273 KQ=σεA(Tenv4–T4)r = 1 \;cm = 0.01 \;m \\ T_{env}=10\; C = 283 \;K \\ T = 0\; C = 273 \;K \\ Q = σεA(T_{env}^4 – T^4)r=1cm=0.01mTenv=10C=283KT=0C=273KQ=σεA(Tenv4–T4)
σ=5.6704×10−8 Wm2K4σ = 5.6704 \times 10^{-8} \; \frac{W}{m^2K^4}σ=5.6704×10−8m2K4W Stefan Boltzmann constant
ε = 1 (for black body)
A=πr2Q=5.6704×10−8×1×3.14×(0.01)2(2834–2734)Q=0.015 WA = πr^2 \\ Q = 5.6704 \times 10^{-8} \times 1 \times 3.14 \times (0.01)^2(283^4 – 273^4) \\ Q = 0.015\; WA=πr2Q=5.6704×10−8×1×3.14×(0.01)2(2834–2734)Q=0.015W
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