Question #248054
A 50n gun fires a 1.0 gram bullet at a speed pf 2200 m/s. what is the speed pf gun recoil?
1
Expert's answer
2021-10-07T08:50:48-0400

Let's first find the mass of the gun:

mg=50Ng=50N10m/s2=5kgm_g = \frac{50N}{g} = \frac{50N}{10m/s^2} = 5kg

where g=10m/s2g=10m/s^2 is the gravitatinal acceleration.

The momentum of the bullet is:

pb=mbvb=0.001kg×2200m/s=2.2kgm/sp_b = m_bv_b = 0.001kg \times 2200m/s = 2.2kg⋅m/s

Then, according to the momentum conservation law, the momentum of the gun has the same magnitude:

pg=pb=2.2kgm/sp_g = p_b = 2.2 kg⋅m/s

The speed of gun then:

vg=pgmg=2.2 kgm/s5kg=0.44m/sv_g = \frac{p_g}{m_g} = \frac{2.2\space kg\cdot m/s }{5kg}=0.44m/s


Ans. 0.44m/s



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