Let's first find the mass of the gun:
mg=g50N=10m/s250N=5kg
where g=10m/s2 is the gravitatinal acceleration.
The momentum of the bullet is:
pb=mbvb=0.001kg×2200m/s=2.2kg⋅m/s
Then, according to the momentum conservation law, the momentum of the gun has the same magnitude:
pg=pb=2.2kg⋅m/s
The speed of gun then:
vg=mgpg=5kg2.2 kg⋅m/s=0.44m/s
Ans. 0.44m/s
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